Wednesday, January 11, 2012

If a pro basketball player has a vertical leap of 20 inches, what is his hang time?

If a pro basketball player has a vertical leap of 20 inches, what is his hang time? Use the hang time function V=48 T2. Simplify your answer, round to the nearest tenth, and type as an integer or a decimal.If a pro basketball player has a vertical leap of 20 inches, what is his hang time?
Hang time function....

Velocity = 48t虏

Find his initial velocity as he leaves the ground...

v虏 = 2gh

g = gravity = 32.2 ft/s虏

v = 鈭歔(2)(32.2)(20 / 12)]

v = 10.36 ft/s

Plug back into the hang time function...

10.36 = 48t虏

t = 鈭?10.36 / 48)

t = 0.5 s %26lt;======================

Rounded to the nearest tenthIf a pro basketball player has a vertical leap of 20 inches, what is his hang time?
from the formula:

V=48 T2

T2=V/48=20/48

T=0.645If a pro basketball player has a vertical leap of 20 inches, what is his hang time?
I thought it all depended on what he was hanging from.
0.645 seconds = t (hang time)

No comments:

Post a Comment